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JayPaxman
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Re: Jan 16 - Part 3. Low-Power Peripherals
JayPaxman   1/16/2013 5:48:55 PM
NO RATINGS
Actually, as BruceMcLaren points out, we are not talking about Ohm's Law here, where the voltage is applied to a fixed impedance (R or Z).  We are talking about I=CdV/dt, the charging of capacitances.  So P = VI   and   P = V * C * dV / dt   where the dV would equal V, since the internal logic swing for the MCU will be rail to rail.   and  1/dt  is the frequency.  So now you have  P = V * C * V * f  or  P = V^2 * f * C



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